Test link for teachchemistry issue report.

$\ce{(^{227}_{90}Th+)}$

$\ce{CO2 + C -> 2 CO}$

$\ce{Volume = πr^2h = π * ({$\frac{diameter}{2}$}) * thickness}$

During alpha (𝜶) decay, a helium nucleus ($\ce{^{4}_{2}He}$), containing 2 protons and 2 neutrons, breaks off of the nucleus emitting energy. Alpha decay occurs when the nucleus has too many protons compared to neutrons. The resulting nucleus is a different element as it contains 2 fewer protons and neutrons. The total mass of the nucleus decreases.